Question

Determine k so tht k square+4k+8,2k square+3k+6,3k square+4k+4 are the three consecutive terms of an ap

Answer 1

consecutive terms in AP ⇒ there is a constant difference

Form equation:

(2k² + 3k + 6) - (k² + 4k + 8) = (3k² + 4k + 4) - (2k² + 3k + 6)

2k² + 3k + 6 - k² - 4k - 8 = 3k² + 4k + 4 - 2k² - 3k - 6

k² - k -2 = k²+ k -2

2k = 0

k = 0

Answer: k = 0