Question

determine magnetic moment of MN in KMnO4​

Answer 1

Answer:

Oxidation number of Mn in MnO4−=+7it is expected that (Mn in) MnO4− sholud have [Ar] configuration and should be colourless. But one electron is transfered to Mn from oxygen and thus Mn in MnO4− has one unpaired electron making it paramagnetic. Magnetic moment =N(N+2) =3 BM.

Explanation:

Answer 2

The magnetic moment of Mn in KMnO4 is √3.

• KMnO4 is potassium permanganate and its electronic configuration is [Ar]18 3d5 4s2.
• After the loss of 7 electrons, its electronic configuration is [Ar]18 and the d electron is zero but still paramagnetic.
• The magnetic moment is given by
• $\sqrt{n(n + 2)} \: bohrs \: magneton$
• The unit of magnetic moment is Bohr's magneton.
• In KMnO4, the magnetic moment is not zero and paramagnetic because of the presence of 1 electron from charge transfer spectra from oxygen.
• So, the magnetic moment =
• $\sqrt{1(1 + 2)} = \sqrt{3} = 1.732 \: bohrs \: magneton$