Question

determine nature of the roots of quadratic equation ×2+5×-1=0​

Answer 1

Step-by-step explanation:

This is in the form of ax^2+bx+c=0. The co-efficient are a=2,b=−5,c=−1

△=b^2−4ac, △=(−5)^2−4(2)(−1),

△=25+8,△=33

∴△>0. Therefore, roots are real and distinct