Determine of AP whose 3rd term is 16 and when 5th term is subtracted from 7th term we get 12.
CLASS 10TH CBSE SAMPLE PAPER 2018-19
MATHEMATICS
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Answered by
113
let a be 1st term n d be the common difference
3rd term= a+2d=16
5th term= a+4d
7th term= a+6d
7th term - 5th term= 2d=12
=> d=6
hence a+2d=16
=> a=4
hence AP is 4, 10, 16, 22, 28, 34, 40......
3rd term= a+2d=16
5th term= a+4d
7th term= a+6d
7th term - 5th term= 2d=12
=> d=6
hence a+2d=16
=> a=4
hence AP is 4, 10, 16, 22, 28, 34, 40......
Answered by
41
I think that's the answer. Seems simple was that a homework
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