Math, asked by PragyaTbia, 1 year ago

Determine order and degree (if defined) of differential equation: \biggr\lgroup\frac{d^2y}{dx^2}\biggr\rgroup +cos  \biggr\lgroup\frac{dy}{dx}\biggr\rgroup=0

Answers

Answered by hukam0685
0
Answer:

Order=2

Degree=not defined

Solution:

Order of differential equation: Order is the highest numbered derivative in the equation.

Degree of differential equation: Degree is the highest power to which highest numbered derivative is raised when equation is free from radicals.

\biggr\lgroup\frac{d^2y}{dx^2}\biggr\rgroup +cos \biggr\lgroup\frac{dy}{dx}\biggr\rgroup=0

here highest numbered derivative is 2

So, order is 2

That highest number derivative raised to power 1,but that first order derivative is also with trigonometric function cos,in such case degree is not defined.

Hope it helps you.

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