Question

Determine order and degree (if defined) of differential equation: $\biggr\lgroup\frac{ds}{dt}\biggr\rgroup ^{4} + 3s \frac{d^2 s}{dt}^2=0$

Answer 1

Answer: 

Order=2

Degree=2

Solution:

Order of differential equation: Order is the highest numbered derivative in the equation.

Degree of differential equation: Degree is the highest power to which highest numbered derivative is raised when equation is free from radicals.

$\biggr\lgroup\frac{ds}{dt}\biggr\rgroup ^{4} + 3s\bigg( \frac{d^2 s}{dt}\bigg)^2=0$

here highest numbered derivative is 2

So, order is 2

That highest number derivative raised to power 2

So, it's Degree is 2.

Hope it helps you.