Question

determine the 33rd term of an ap whose 17th term is -20 and the common difference is 3/4

Answer 1

ATQ,

T17=a+16d

-20=a+16×3/4

-20=a+12

a= -32

now,

T33 = a+32d

T33= -32+3/4×32

T33= -32+24

T33= -8