Determine the A.P. whose 4th term is 18 and the difference of the 9th and the 15th term is 30.
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use the basic notation of AP, HOPE THIS HELPS!!
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ATQ
4th term = a+3d.......(1)
ATQ
(a+8d)-(a+14d) = 30
a+8d-a-14d=30
6d=30
d=30/6
d=5........put in eq.(1)
a+3×5=18
a+15=18
a=18-15
a=3
A.P.=a,a+d,a+2d.......
=3,3+5,3+10.....
=3,8,13....
4th term = a+3d.......(1)
ATQ
(a+8d)-(a+14d) = 30
a+8d-a-14d=30
6d=30
d=30/6
d=5........put in eq.(1)
a+3×5=18
a+15=18
a=18-15
a=3
A.P.=a,a+d,a+2d.......
=3,3+5,3+10.....
=3,8,13....
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