Question

Determine the acceleration of the masses w.r.t. lift and tension in the string if the whole system in moving vertically upwards with uniform acceleration a0​. (m1​>m2​) Don't spam stay away spammers

Answer 1

Answer:

Explanation:

let the tension be T

m1(g+a  0 )−T=m1 a

their will be pseudo force on the  m1 and m2 in downwrd direction .

let the tension be

Tm1(g+a0)−T=m1a

T−m2(g+a0)=m2a

add both the eqn

(m1−m2)(g+a0)=a(m1+m2)a

=(m1−m2)(g+a0)(m1+m2)

accn of the blocks wrt the lift .

T=m2(m1−m2)(g+a0)(m1+m2)+m2(g+a0)  tension in the string .

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Answer 2

Given:

• The lift is moving upwards
• The lift has acceleration = Ao
• The Masses are M1 and M2
• M1 > M2

Need to Find:

• The acceleration of masses
• Thesion in string

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♤Let The Tension be T

♤ Let the acceleration of the blocks be A

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☆Apply PseudoForce on blocks M1 and M2

☆The Pseudo Force will be equal to Mass of the body× Acceleration of the non-inertial frame

☆We know in a body mg acts downwards

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Now writing the equations we get,

$\red{M1g+M1A0−T=M1a-----1}$

and

$\red{T−M2(g+A0)=M2a-----2}$

adding both the equation we get, 

(M1−M2)(g+A0)=a(M1+M2) 

$\pink{\bold{a = \dfrac{(M1 - M2)(g + Ao)}{M1 + M2}}}$

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Putting the value of acceleration in equation 2 we get,

T= M2a+M2Ao+M2g

=> T=

$M2 \times \dfrac{(M1 - M2)(g + Ao)}{M1 + M2} + M2(Ao + g)$

$\pink{\bold{T= \dfrac{2M1M2(g + Ao)}{M1 + M2}}}$