DETERMINE THE AMONT OF NACL TO BE DISSOLVED IN 600GR H2O TO DECREASE THE FREEZING POINT BY 0.2CDEGREE GIVEN KF OF H2O =2K/MOL DENSITY OF H2O
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Dear Student,
◆ Answer -
W2 = 1.755 g
● Explanation -
# Given -
W1 = 600 g
∆Tf = 0.2 ℃
Kf = 2 K/m
# Solution -
Elevation of freezing point is given by -
∆Tf = i × Kf × m
∆Tf = i × Kf × (W2/M2) / (W1 / d1)
0.2 = 2 × 2 × (W2/58.5) / (600/1000)
W2 = 0.2 × 0.6 × 58.5 / 4
W2 = 1.755 g
Hence, 1.755 g of NaCl have to be dissolved.
Thanks dear. Hope this helps you...
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