Determine the amount of bromine (in milligrams) in 500 ml of solution of 0.1 m nabr.
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So,
Molarity = moles /volume
So, 0.1 = x/102.8×1000/500
0.1 = x/102.8×2
x = 0.1×102.8/2
= 5.14 gms.
= 5140mg.
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