Question

Determine the amplitude of the resultant wave when the two electric fields interfere. The
intensity of the interference patterns at a point P is 12.0 W/m2
(a) 95.1 N/m
(b) 67.2 N/m
(c) 134 N/m
(d) 9,044 N/m​

Answer 1

Answer:

given = I = 12.00W/m2 point P

to find = amplitude of resultant feild

solution =

I = 1/2 CεοE²

E = √2I/Cεο

C= speed of light which is 8 X 10⁸

ε = PERMABILITY of free space which is 8.85 x 10⁻¹²

apply the formula,

E = $\sqrt{\frac{2X12}{ 8 X 10⁸X8.85 x 10⁻¹²}$

E = 95.07 N/m

E = 95.1N/m

the amplitude of the resultant wave when the two electric fields interfere. is E = 95.1N/m

so, the option 1st (a) is correct.