Math, asked by dass27949, 5 months ago

Determine the angle between the lines of intersection of the plane x-3y + z = 0 and a quadric cone x^2 - 5y^2 + 2 = 0.​

please someone help me

Answers

Answered by Anonymous
6

Answer:

The angle between the lines of intersection of the plane x-3y + z = 0 and a quadric cone x^2 - 5y^2 + 2 = 0 is 360.

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