Question

Determine the AP who is the term is 16 and the seventh term exceeds the 5th term by 12

Answer 1

a7( 7th term)=16 a7-a5=12 ie, 2d=12 ie, d=6. a7=a+6d=16 a+36=16 a=16-36=-20 ie,a= -20 we get the value of first term(a) = -20 and common difference (d)=6 ie, the series is -20, -14, -8, -2, 4, 10, 16,.........