Determine the AP whose 3rd term is 16 and the 7th term exceeds the 5th term by 12
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A +2d =16
If u solve part two of q, u get d as 2
In part 1, a = 16 - d
So as d is 2,
A= 16-2=14
So the Ap is 14,16,18
If u solve part two of q, u get d as 2
In part 1, a = 16 - d
So as d is 2,
A= 16-2=14
So the Ap is 14,16,18
Ankitraja:
Please do by process I didn't understand this answer
And the answer is also wrong
oh sry dude
i will tell it wait
third term = a + 2d = 16 (given)
a+6d = a+4d+12 (given)
so, d=6
now, by substituting, u get a = 4
now u know, a=4 and d=6
so the Ap is 4,10,16...........
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