Question

determine the AP whose third term is 16 and 7th term exceeds the 5th term by 12.​

Answer 1

Step-by-step explanation:

a+6d=a+5d

6d-5d=12

d=12

and

a+2d=16

a=-8

Answer 2

T3=>a+2d=16_eq1

A/C to que_

T7=T5+12

a+6d=a+4d+12

2d=12

d=6

Put d value in eq1:_

a+12=16

a=4

Required AP=4,4+6,4+6+6, _, _, _

=4, 10, 16, _, _, _

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