Question

Determine the AP whose third term is 16 and the 7 term exceeds the 5th term by 12

Answer 1

Given- AP whose third term is 16 and the 7 term exceeds the 5th term by 12

3rd term = a+ (n-1)d = a+2d= 16
7th  term = a+6d
5th term = a+4d

7th term- 5th term = 12
2d =12

d = 6

Now, a= 16- 2*6 = 4

hence, a=4 and d=6

So, the terms of A.P

4,10,16,22,28,34,40,46,52..........

Answer 2

Heya mate !! see ur ans.