Math, asked by kajalshah, 1 year ago

If x+y+z=1, x^2+y^2+z^2=2 and x^3+y^3+z^3=3, find the value of xyz.

Answers

Answered by sanakhan14

0

X= -1
Y=1
Z = - 1
Respectively
Hope it helps u......

kajalshah: The options are:-

kajalshah: A 1/5

kajalshah: B 1/6

kajalshah: And C 1/7

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