Question

Determine the AP whose third term is 16 and the 7th term exceeds the 5th term by 12.​

Answer 1

Ur answer is attached mate.

Pls mark brianiliest if it helps...

Answer 2

Answer:

3rd term is 16

a + 2d = 16

7th term - 5th term is 12

a + 6d -(a+4d) =12

a + 6d - a - 4d =12

2d = 12

d = 6

as

a + 2d = 16

a + 2×6 = 16

a + 12 = 16

a = 16 -12

a= 4

hence AP is 4, 10, 16.......