Question

Determine the AP whose third term is 16 and the 7th term exceeds the 5th term by 12.

Answer 1

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Answer 2

Answer:

4, 10, 16, 22, 28, ......

Step-by-step explanation:

Let the A.P. is a, (a+d), (a+2d), ..... up to n the terms.

Where a is the first term. d is the common difference and n is the number of terms.

Now, the 3rd term =(a+2d) =16 ...... (1) (Given)

Again it is said that the 7th term exceeds the 5th term by 12.

Therefore, (a+6d)-(a+4d) =12

⇒ 2d =12

⇒ d=6.  

Now, from equation (1), we get, (a+12) =16, ⇒ a= 4.

Therefore, the A.P. will be,  

4, 10, 16, 22, 28, ...... (Answer)