Question

Determine the APwhose fourth term is 16 and the 9th term exceeds the 7th term by 10.

Answer 1

Answer:

Step-by-step explanation:

4th term in an AP can be written as a+3d where a is first term d is common difference

so a+3d=16

similarly 9th term is a+8d and 7th term is a+6d

given a+8d=a+6d+10

gives 2d=10

so d=5

now a+3(5)=16

a=1

so the AP is starting with 1 and has a common difference of 2

so it is the AP of odd natural numbers

I HOPE THIS HELPS YOU

Answer 2

Answer:

see attached file for your answer