Determine the average power absorbed by delta connected load Z2 = 30 + j27 12.
100/0° V rms
192
ww
j0.5 12
+
ZA
100/-120° V rms
132 j0.5 12
WWm
+
ZA
1
ZA
100/120° V rms
192
j0.5 2
+
(A) Pang = 1410 W
(B) Prs = 1420 W
(C) P. = 1430 W
(D) P=1440 W
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Answer:
Prs = 1420 W this is right answer of this question
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