Question

determine the boiling point of 1 m solution of sugar ,glucose , urea,sodium chloride, barium chloride,,alluminium chloride

Answer 1

Determine the boiling points of 1M solutions of sugar,glucose,urea,sodiam chloride,barium chloride,aluminium chloride

Answer 2

Explanation:

Elevation in boiling point = $\Delta T_b$

$\Delta T=T_b-T$

$\Delta T_b=i\times K_b \times m$

T = Boiling point of pure solvent

$T_b$= Boiling point of solution

Molality of solution = m

$K_b$ = Molal elevation constant

i = van't Hoff factor

Values of T=100°C, $K_f=0.52^oC/m$,m will remain same but value of i will be different:

Boiling point of 1 m solution of sugar

i = 1

$\Delta T_b = 1\times 0.52^oC/m\times 1m=0.52^oC$

$T=100^oC+0.52^oC=100.52^oC$

Boiling point of 1 m solution of glucose

i = 1

$\Delta T_b = 1\times 0.52^oC/m\times 1m=0.52^oC$

$T=100^oC+0.52^oC=100.52^oC$

Boiling point of 1 m solution of urea

i = 1

$\Delta T_b = 1\times 0.52^oC/m\times 1m=0.52^oC$

$T=100^oC+0.52^oC=100.52^oC$

Boiling point of 1 m solution of sodium chloride

i = 2

$NaCl(aq)\rightarrow Na^+(aq)+Cl^-(aq)$

$\Delta T_b = 2\times 0.52^oC/m\times 1m=1.04^oC$

$T=100^oC+1.04^oC=101.04^oC$

Boiling point of 1 m solution of barium chloride

$BaCl_2(aq)\rightarrow Ba^{2+}(aq)+2Cl^-(aq)$

i = 3

$\Delta T_b = 3\times 0.52^oC/m\times 1m=1.56^oC$

$T=100^oC+1.56^oC=101.56^oC$

Boiling point of 1 m solution of aluminium chloride

$AlCl_3(aq)\rightarrow Al^{3+}(aq)+3Cl^-(aq)$

i = 4

$\Delta T_b = 4\times 0.52^oC/m\times 1m=2.08^oC$

$T=100^oC+2.08^oC=102.08^oC$