determine the current density in an aluminium wire of length 2.00 m amd radius 0.650 cm. the potential difference between the ends of wire is 60.0 V.
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Given :
- Length of wire = 2.00 m
- Radius of wire = 0.650 m
- Potential difference between the ends of wire = 60.0 V
To find :
• Current density
Solution :
• We know that, current density is given by
J = I / A
where I = current flowing in wire and A = cross section area of wire
J = (V/R)×(1/A)
R = rho×L / A
• Therefore,
J = (V×A / rho×L)×(1/A)
= V / rho×L
• We do not have value of specific resistance in question, So we cannot proceed further.
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