English, asked by davarichaitanya17, 1 month ago

Determine the current flowing through
Galvnometer.​

Answers

Answered by Anonymous
3

Answer:

Therefore the current flowing through these two resistors in series is given as: V/RT.

I = V ÷ R = 12V ÷ (10Ω + 20Ω) = 0.4A.

VR2 = I × R2 = 0.4A × 20Ω = 8 volts.

VR4 = 0.4A × 10Ω = 4 volts

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