Question

Determine the discriminant of each quadratic equation, then state the number and type of solutions.
a) 9x2 + 4x + 6 = 0
b) 9m2 - 6m + 1 = 0

Having trouble with this one, help pls

Answer 1

Answer:

can't answer the sum is in long explanation so sorry

Answer 2

QUESTION:

Determine the discriminant of each quadratic equation, then state the number and type of solutions.

a) 9x2 + 4x + 6 = 0

b) 9m2 - 6m + 1 = 0

ANSWER :

To find the discriminant, we use the formula.

$d = \sqrt{ {b}^{2} - 4ac}$

where :

$b = middle \: term$

$a = coefficient \: of \: x \: square$

$c = constant \: term$

a)

$9 {x}^{2} + 4x + 6 = 0$

here,

$a = 9 \\ b = 4 \\ c = 6$

$\sqrt{ {4}^{2} - 4 \times 9 \times 6 } \\ \sqrt{16 - 216} \\ \sqrt{ - 200} \\ \\ - 10\sqrt{2} (unequal \: roots \: as \: dicriminant \: is \: less \: than \: 1)$

$9 {m}^{2} - 6m + 1 = 0$

here

$a = 9 \\ b = - 6 \\ c = 1$

$\sqrt{ {9}^{2} - 4 \times 6 \times 1 } \\ \sqrt{81 - 24} \\ \sqrt{57} (real \: and \: equal \: roots \: as \: it \: is \: greter \: than \: 1)$

PLZ MARK AS BRAINLIEST