Question

Find the smallest no., which when
ii) increased by 3 is exactly divisible by the no's 21, 45, 63
81 and 210.​

Answer 1

First we have to find LCM of 21, 45, 63, 81, 210

we will get 5670.

To find the number exactly divisible by 3, we have to subtract 3 from 5670

=>5670-3=5667.

Therefore answer is 5667.