Question

Determine the electric charge acquired by an object when it loses 2 electrons and when it gains 3 electrons

Answer 1

Answer:

I) 3.2 × 10 ⁻¹⁹ Coulomb

I) 4.8 × 10 ⁻¹⁹ Coulomb

Explanation:

We know that charge on a single electron is 1.6 × 10 ⁻¹⁹ Coulomb . This value is denoted by q.

Thus if charge on one electron is 'e'. Thus charge on 'n' election will 'ne'

If we denote total charge by Q,

Q = ne

Unit of Q is Coulomb

Case I:-

Number of electrons (n) = 2

We know that total charge,

Q = ne

Q = 2 × 1.6 × 10 ⁻¹⁹

Q = 3.2 × 10 ⁻¹⁹ Coulomb

In this case object it lossing the electron so it will be positively charged as compared to Initial Stage.

Case II:-

Number of Electrons (n) = 3

We know that total charge,

Q = ne

Q = 3 × 1.6 × 10 ⁻¹⁹

Q = 4.8 × 10 ⁻¹⁹ Coulomb

In this case object is gaining the electron so it will be negatively charged as compared to Initial Stage

Answer 2

Given :-

An object loses 2 electrons and gains 3 electrons.

To determine :-

The electric charge acquired by the object when it loses 2 electrons and gains 3 electrons.

Acknowledgement :-

Charge is denoted by Q.

Q of an electron = 1.6 × 10⁻¹⁹ Coulomb.

If we have 'n' number of electrons, and the charge of a single electron is 'e', then the total charge becomes: Q = ne

Solution :-

When it loses 2 electrons, we have :

• Number of electrons(n) = 2

• Charge(e) = 1.6 × 10⁻¹⁹ Coulomb

• Total charge(Q) = ne

⇒Q = 2 × 1.6 × 10⁻¹⁹

⇒Q = 3.2 × 10⁻¹⁹ Coulombs

When it gains 3 electrons, we have :

• Number of electrons(n) = 3

• Charge(e) = 1.6 × 10⁻¹⁹ Coulomb

• Total charge(Q) = ne

⇒Q = 3 × 1.6 × 10⁻¹⁹

⇒Q = 4.8 × 10⁻¹⁹ Coulombs

So, the overall electric charge acquired is :

4.8 × 10⁻¹⁹ - 3.2 × 10⁻¹⁹ = 1.6× 10⁻¹⁹

∴ So, when the object loses 2 electrons and gains 3 electrons, then the electric charge acquired by it is 1.6× 10⁻¹⁹ C. This shows that, the object is finally negatively charged.

∴ When the object loses 2 electrons, its charge is 3.2 × 10⁻¹⁹ and when it gains 3 electrons, its charge is 4.8 × 10⁻¹⁹.