Question

if 1/a,1/b,1/c are in AP , ab+bc+ac=24 then find the value of ac.​

Answer 1

Step-by-step explanation:

1/a , 1/b & 1/c are in A.P.

2(1/b) = 1/a + 1/c

2/b = (a + c)/ac

2ac = b(a + c)

2ac = ab + bc

ab + bc = 2ac --------(1)

Now ,

ab + bc + ac = 24

2ac + ac = 24

3ac = 24

ac = 8

I hope it will help you

Answer 2

Answer:

8

Step-by-step explanation:

Given,

1/a,1/b,1/c are in A. P

ab + bc + ca = 24 - - - - - (1)

2(1/b)=1/a+1/c

2/b = (a + c) /ac

2ac = b(a + c)

2ac = b(a + c)

2ac = ab + bc

**ab + bc = 2ac

Now substitute this in eq (1)

ab + bc + ca = 24

2ac + ac = 24

3ac = 24

ac = 24/3

****ac = 8****

I HOPE THIS MAY HELP YOU