Question

Determine the equation of the line passing through (6,-2),if the sum of its intercepts on the axes is 5

Answer 1

Answer:

let intercepts be (a,0)and (0,b)

slope m=-b/a

given a+b=5

also m=-(b+2)/6

-(b+2)/6=-b/a

6b=ab+2a

put a=b-5

We get b=-5 or b=2

a=0 a=3

hence eqn is x/3+y/2=1