Question

Determine the escape speed of a body on the moon. Given : radius
of the moon is 1.74 × 10^6 m and mass of the moon is 7.36 × 10^22 kg.

Answer 1

Given radius of the moon is d= 1.74x 10^6meters( actually its the dimater value not radius) Mass= 7.36 x 10^22 Kg// The gravity G = 6.67 x 10^-11 N.m^2/kg ^2 ESCAP velocity formula V= sqr 2{GM / d} -----= sqr 2 (6.67 x10^-11)(7.36 x10^22)/1.74 x10^6 -----= 2370 meters /second is the escap velocity of moon...

Answer 2

escape velocity is v =√{(2GM)/r}
here G = gravitational constant =6.67384 × 10⁻¹¹$m ^{3} kg^{-1}s^{-2}$
so given radius
of the moon is 1.74 × 10⁶ m and mass of the moon is 7.36 × 10^22 kg.
equating v we get 2375.82 m/s