Question

determine the escape velocity of the body of the moon. Given:radius of the moon is 1.74×10^6m and mass of moon is 7.36×10^22. Explain the above answer.

Answer 1

Ve = $\sqrt{ \frac{2G M}{R} }$ 

Ve =$\sqrt{ \frac{( 2 ). 6.67 10^{-11} . (7.36 10^{22} ) }{ 1.74 10^{ 6 } } }$

Ve = 2.375 × 10³ m/s 

Answer 2

Answer:

please mark as brainliest

Explanation:

please follow me