Determine the frictional force of the air on a body of mass 0.25 kg falling with an acceleration of 9.2 m/s2 ???
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Answer:
0.150 N
Explanation:
In this question, we should first draw the free body diagram and that we will observe that:
Net force,
mg-f=ma where f is force of friction.
0.25(9.8)-f=0.25(9.2)
f=0.25(0.6)
f=0.150 N.
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