determine the greatest 3-digit numbers exactly divisible by 8,9and12
yasica:
smallest 3-digit number divisible by 8,10,12 =120 .and greatest no of 3-digit = 120*8=960.
i think 999
it is not the right answer
risht answer is 960
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greatest 3 - digit no. is 8*10*12=960
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Prime factorization of
8=2×2×2
10=2×5
12=2×2×3
LCM of (8,10and 12) =2×2×2×3×5=120
Largest three digit number which is divible by 120 is 960
Hence,the required number is 960
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