Question

Determine the greatest natural numbers Which when divided by 12,16,24 and 36 leaves remainder 7 in each case?​

Answer 1

Answer:

Least number when divided by 12,16,24,36 and leaves remainder 0

=LCM of 12,16,24,36

So,LCM leaves remainder 0

So,Required number will be 7 more than LCM

∴ Required number=LCM+7

Factors of 12=2×3×2

Factors of 16=2×2×2×2

Factors of 24=2×2×2×3

Factors of 36=2×2×3×3

∴ LCM=2×2×2×2×3×3=16×9=144

So,Required number=LCM+7=144+7=151

plzzz mark it as brainliest.......

and plzzzzzzzzzz follow me....!!!!

Answer 2

Answer:

The smallest number which divides 12 16 24 and 36 is 144. But we have a condition that it leaves a remainder of 7. So we add 7 to the LCM (144+7=151). Hence the smallest number that when divided by 12 16 24 and 36 leaves a remainder 7 is 151...