Question

determine the horizontal force required to dispace a mass of 0.03 kg suspended by a string until the string makes an angle of 30° with the vertical. ​

Answer 1

hi mate

here is your answer

Given,m = 0.03 kg. angle = 30°

now,

Using the law of conservation of mechanical energy =>>

Work done by the horizontal force = Gain in P. E. of mass 0.03kg

also,work done= F×a

So, F × 1 sin 30° = mg × ( 1 - 1 cos 30°)

=>> F = mg × (1 -1 cos 30°)/1 sin 30°

=>>F = 0.03 g × (1 - √3/2)/(1/2)

=>>F = 0.03 g × (2 - √3)

=>>F = 0.03 × 9.8(2-√3).

(since we assume g to be 9.8m/s^2)

=>>F = 0.079Newton.

hope it helps

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