Determine the largest area of the rectangle whose base is on the x-axis and the two vertices lie on the curve y-e^-x^2
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Step-by-step explanation:
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Let's t1 and t2 the abscissas of the lower vertices (t2>t1) and clearly the upper vertices have the ordinates
12−t21=12−t22⟺t1=−t2sincet1≠t2
and the area of the rectangle is
(t2−t1)(12−t21)=2t2(12−t22)
hence to answer the question we should maximize the function
f(t)=t(12−t2)
and since
f′(t)=12−t2−2t2=12−3t2=0⟺t=±2
hence we see easily that t2=2 and the area is
2f(2)=32
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