Determine the length of CD
Attachments:
Answers
Answered by
0
Answer:
Solution
verified
Verified by Toppr
In △AED,
AE/DE=tan22
0
AE=DEtan22
0
=15×0.404
AE=6.06m
In △ABC,
AB/BC=tan47
0
AB=BCtan47
0
=15×1.072
AB=16.09m
Thus,
CD=BE=AB−AE=16.09−6.06=10.03m
Similar questions