Question

Determine the length of the altitude of an isosceles triangle of sides 6cm, 6cm and 4cm.​

Answer 1

Answer:

The length of the altitude of an isosceles triangle of sides 6cm, 6cm and 4cm is $\sqrt[2]{4}$ .

Step-by-step explanation:

As per the question:

Given That:

the length of the altitude of an isosceles triangle of sides 6cm, 6cm and 4cm.​

To Find:

To determine the length of the altitude of an isosceles triangle of sides 6cm, 6cm and 4cm.​

Solution:

As per the question we know that the length of AB side and length of AC side is equal to 6cm.

This is given question.

AB=AC=6cm

Then BC will be 4cm

BC=4cm

BD=4/2

=2 cm

$AD^2= AB^2 - BD^2= 6^2 - 2^2$

= 36 - 4

So,

AD = √32

=2√4

Therefore, the length of the altitude of an isosceles triangle of sides 6cm, 6cm and 4cm is $\sqrt[2]{4}$.

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Answer 2

Answer:

An isosceles triangle with sides of 6, 6, and 4 cm has an altitude of cm.

Detailed explanation:

According to the query:

Due to That:

the height of an isosceles triangle with sides of 6, 6, and 4 cm.

To Locate:

to calculate the altitude of an isosceles triangle with sides of 6, 6, and 4 cm.

Solution:

According to the inquiry, we are aware that the lengths of the AB and AC sides are both 6 cm long.

The question is as stated.

AB=AC=6cm

BC will then be 4 cm.

BC=4cm

BD=4/2

=2 cm

= 36 - 4

So,

AD = √32

=2√4

Thus, the altitude of an isosceles triangle with sides of 6, 6, and 4 cm is.

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