Question

Determine the locus of points P(x,y) such that P is equidistant from (0,2) and y= -2

Answer 1

Answer:

p(x,y)=(-4,-2)

Step-by-step explanation:

p(x,-2) and (0,2)

√(x-0)^2+(2+2)^2=√x^2+(4^2);

=x+√16=x+4;

x=-4