Determine the magnitude of magnetic field at the centre of the current carrying wire arrangement
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We know from Biot Savart law that the magnetic field due to a small current element is given by
dB=[(Π/4π)×i(dl)sin(α)]/r²
where Π is the absolute permeability of the medium .
In the case of close current carrying loop,
α=π/2.
dB=(Π/4π).i.(dl)/r²
integrating for the whole loop we get
B=Πi/2r.
dB=[(Π/4π)×i(dl)sin(α)]/r²
where Π is the absolute permeability of the medium .
In the case of close current carrying loop,
α=π/2.
dB=(Π/4π).i.(dl)/r²
integrating for the whole loop we get
B=Πi/2r.
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