Question

Determine the mass (in g) of nitric acid (hno3) in 60.00 cm3 of a 3.00 mol dm-3 solution. Give the answer to three significant figures

Answer 1

Answer: 11.3 grams.

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per Liter of the solution.

$Molarity=\frac{n\times 1000}{V_s}$

where,

Molarity =$3.00mol/dm^3 =3.00mol/L$    $(1dm^3=1L)$

n= moles of solute  

$V_s$ = volume of solution in ml = 60 ml           $(1cm^3=1ml)$

$moles of solute =\frac{\text {given mass}}{\times {\text {molar mass}}=\frac{xg}{63g/mol}$

Now put all the given values in the formula of molarity, we get

$3.00mol/L=\frac{xg\times 1000}{63g/mol\times 60ml}$

$x=11.34g$

Therefore, the mass of nitric acid is 11.3 grams.