Question

in a factory 203 workers are working they have been divided in a b and c Groups for distribution of Bonus the amount of Bonus had been divided in 4 is to 3 is to 2 ratio but the workers of every group received the amount of Bonus in the ratio of 3 is to 2 is to 1 find out the number of workers of every group ​

Answer 1

Answer:

a=56, b=63, c=84.

Step-by-step explanation:

Let us assume that,

in group 1 there are a workers,

in group 2 there are b workers,

in group 3 there are c workers.

Now, the individual workers from groups 1, 2 & 3 get Bonus in the ratio 3:2:1.

Then, each worker from group 1 gets bonus of 3m (say). So, the total bonus in group 1 is 3ma.

And, each worker from group 2 gets bonus of 2m (say). So, the total bonus in group 2 is 2mb.

Again, each worker from group 3 gets bonus of m (say). So, the total bonus in group 3 is mc.

From the given conditions, it can be written that,

3ma : 2mb : mc = 4:3:2

⇒3a : 2b : c = 4:3:2

Hence, we can write from the above equation,  

$\frac{3a}{2b}=\frac{4}{3}$

⇒a/b=8/9

Again, $\frac{2b}{c}=\frac{3}{2}$

⇒b/c= 3/4=9/12

Hence, a:b:c=8:9:12

So, in group 1 there are $\frac{203*8}{8+9+12}=56$ workers.

And in group 2 there are $\frac{203*9}{8+9+12}=63$ workers.

And in group 3 there are $\frac{203*12}{8+9+12}=84$ workers.

(Answer)