Question

determine the mass of 3.011*10^23 molecules of Cu(NO3)2. (Cu=65.5u)​

Answer 1

Answer

=214=7g of N.

Explanation:

3.011×1023 no. of nitrogen atom at mass of nitrogen =14g

1 mole of nitrogen contains 6.022×1023 atoms

14g will contains 6.022×1023 atoms

how,

6.022×102314g contains 1 atom

∴(6.022×102314)×3.011×1023

=214=7g of N.