Question

Determine the mass of aluminum acetate if we start the reaction with 125 grams of acetic acid and 275 grams of aluminum hydroxide​

Answer 1

Explanation:

I hope I am help you please mark your brainlist

Answer 2

Given:

125 grams of acetic acid and 275 grams of aluminum hydroxide​

$125 \mathrm{~g} \mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2} \mathrm{H}\times \frac{\text { 1 mole }}{60 g}\times\frac{1 mole\mathrm{Al}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2}\right)_{3}}{3 \mathrm{~mol} \mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2} \mathrm{H}} \times \frac{240 g}{1 mole}$

$141.7 g \mathrm{Al}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}\right)_{3$

$275 \mathrm{~g} \mathrm{Al}(\mathrm{OH})_{3} \times \frac{\mathrm{1mole}}{78 \mathrm{~g}} \times \frac{1 \mathrm{~mole} \mathrm{Al}\left(\mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}\right)_{3}}{1 \mathrm{~mole} \mathrm{C}_{2} \mathrm{H}_{3} \mathrm{O}_{2} \mathrm{H}} \times \frac{2049}{1 \mathrm{~mole}}$

$719.67g \mathrm{Al}\left(\mathrm{C}_{2} \mathrm{H}_{3}(\mathrm{O})_{3}\right.$

Hence 141.7 g aluminum hydroxide​ produced