Question

Determine the molarity of the given KMnO, solution with the help of supplied
Mohr's salt solution by titration method.​

Answer 1

Answer:

Consider y ml of given KMnO4 solution are equivalent to 20ml of N/10 Mohr’s salt solution.

According to law of equivalents,

N1V1 = N2V2

N1, N2 are normality of Mohr’s salt and KMnO4 solution respectively.

V1, V2 are volume of Mohr’s salt and KMnO4 respectively.

1/10 x 20 = N2 x y

N2 = 2/y

N = Normality of given KMnO4 solution = 2/y

(b) Strength of KMnO4 solution:

Strength = Normality x Equivalent mass

Equivalent mass of KMnO4 =

= 158/5

= 31.6

= 2/y x 31.6 g/liter

Molarity of KMnO4 solution

N = M x Number of electron gained

N = M x 5

M = N/5 moles/ litre

The strength of and molarity of given KMnO4 solution is found out as 2/y x 31.6 g/l and N/5 moles/liter respectively.