Question

determine the nature of root of the following quadratic equation from there discriminant x² - 4x + 4 = 0 ​

Answer 1

Given :-

• Quadratic equation : x² - 4x + 4 = 0.

To Find :-

• The nature of roots.

Solution :-

Given that, x² - 4x + 4 = 0

On comparing with ax² + bx + c = 0 , We get :

➡ a = 1 , b = -4 , c = 4

As we know that,

$\large \frak\red{Δ = b² - 4ac}$

➡ Δ = (-4)² - 4 × 1 × 4

➡ Δ = 16 - 16

➡ Δ = 0

$\rm \frak \blue{.°. \: Δ \: = \: 0}$

Hence,

• The roots are real and equal.

Answer 2

Answer:

To Find:

• Nature of the roots

Formula Used :

$\bf \huge \boxed { \red{D \: = {b}^{2} - 4ac}}$

Solution:

we know that,

• given quadratic equations is x²-4x+4 = 0
• These above equation is comparing to standard form of quadratic equations, i.e, ax²+bx+c =0

now,

• a = 1
• b= -4
• c= 4

Then,

>> D = b²-4ac

>>D = (-4)²-4(1)(4)

>>D = 16-16

>>D = 0

•°• Nature of the roots are real and equal !!!!