Question

determine the nature of root x^2-4x+4=0 *

Real and not equal

Real and equal

Equal

Real​

Answer 1

x²-4x+4= 0

here

a=1; b= -4; c=4

to find the what will be the mature pf the roots, we will first find its discriminate ‘D’

D= b²-4ac

=(-4)² - 4(1)(4)

= 16 - 16

= 0

Here, b²-4ac = 0

therefore the nature of the roots of this equation is real & equal.