determine the nature of roots of 2x*2-2x+9=0
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Step-by-step explanation:
Comparing x²+2x-9=0 with ax²+bx+c=0 we get,
a=1,b=2,c=-9
b²-4ac=2²-4 X 1 X -9
=4-(-36)
=4+36
=40
b²-4ac>0
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