determine the nature of roots of 2x2+x-1=0
hsbbzvsvsmss:
real and distinct
Answers
Answered by
7
D = b2 - 4ac
a=2 b= 1 c= (-1)
D = (1)2 - 4(2)(-1)
= 2 - (-8)
= 2 + 8 = 10
here, D>0
so the roots will be real and distinct.
a=2 b= 1 c= (-1)
D = (1)2 - 4(2)(-1)
= 2 - (-8)
= 2 + 8 = 10
here, D>0
so the roots will be real and distinct.
Answered by
5
Answer:
D= B2 - 4ac
D= 1 - 4[2][-1]
D= 1 +8 = 9
here, d > 0 so the roots are real and unequal.
Step-by-step explanation:
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